# How to get the indices list of all NaN value in numpy array?

Say now I have a numpy array which is defined as,

```
[[1,2,3,4],
[2,3,NaN,5],
[NaN,5,2,3]]
```

Now I want to have a list that contains all the indices of the missing values, which is `[(1,2),(2,0)]`

at this case.

Is there any way I can do that?

np.isnan combined with np.argwhere

```
x = np.array([[1,2,3,4],
[2,3,np.nan,5],
[np.nan,5,2,3]])
np.argwhere(np.isnan(x))
```

output:

```
array([[1, 2],
[2, 0]])
```

From: stackoverflow.com/q/37754948