How can I compare two ordered lists in python?

If I have one long list: myList = [0,2,1,0,2,1] that I split into two lists:

    a = [0,2,1]
    b = [0,2,1]

how can I compare these two lists to see if they are both equal/identical, with the constraint that they have to be in the same order?

I have seen q asking to compare two lists by sorting them, but in my specific case, I am not checking for a sorted comparison, but identical list comparison.

Just use the classic == operator:

    >>> [0,1,2] == [0,1,2]
    True
    >>> [0,1,2] == [0,2,1]
    False
    >>> [0,1] == [0,1,2]
    False

Lists are equal if elements at the same index are equal. Ordering is taken into account then.

From: stackoverflow.com/q/36420022

Back to homepage or read more recommendations: