Pythonic way to avoid "if x: return x" statements

I have a method that calls 4 other methods in sequence to check for specific conditions, and returns immediately (not checking the following ones) whenever one returns something Truthy.

    def check_all_conditions():
        x = check_size()
        if x:
            return x

        x = check_color()
        if x:
            return x

        x = check_tone()
        if x:
            return x

        x = check_flavor()
        if x:
            return x
        return None

This seems like a lot of baggage code. Instead of each 2-line if statement, I'd rather do something like:

    x and return x

But that is invalid Python. Am I missing a simple, elegant solution here? Incidentally, in this situation, those four check methods may be expensive, so I do not want to call them multiple times.

You could use a loop:

    conditions = (check_size, check_color, check_tone, check_flavor)
    for condition in conditions:
        result = condition()
        if result:
            return result

This has the added advantage that you can now make the number of conditions variable.

You could use map() + filter() (the Python 3 versions, use the future_builtins versions in Python 2) to get the first such matching value:

    try:
        # Python 2
        from future_builtins import map, filter
    except ImportError:
        # Python 3
        pass

    conditions = (check_size, check_color, check_tone, check_flavor)
    return next(filter(None, map(lambda f: f(), conditions)), None)

but if this is more readable is debatable.

Another option is to use a generator expression:

    conditions = (check_size, check_color, check_tone, check_flavor)
    checks = (condition() for condition in conditions)
    return next((check for check in checks if check), None)

From: stackoverflow.com/q/36117583