Python if not == vs if !=
What is the difference between these two lines of code:
if not x == 'val':
if x != 'val':
Is one more efficient than the other?
Would it be better to use
if x == 'val': pass else:
dis to look at the bytecode generated for the two versions:
4 0 LOAD_FAST 0 (foo) 3 LOAD_FAST 1 (bar) 6 COMPARE_OP 2 (==) 9 UNARY_NOT 10 RETURN_VALUE
4 0 LOAD_FAST 0 (foo) 3 LOAD_FAST 1 (bar) 6 COMPARE_OP 3 (!=) 9 RETURN_VALUE
The latter has fewer operations, and is therefore likely to be slightly more efficient.
It was pointed out in the commments (thanks, @Quincunx) that where you have
if foo != bar vs.
if not foo == bar the number of operations is exactly the same, it's just that the
COMPARE_OP changes and
POP_JUMP_IF_TRUE switches to
not == :
2 0 LOAD_FAST 0 (foo) 3 LOAD_FAST 1 (bar) 6 COMPARE_OP 2 (==) 9 POP_JUMP_IF_TRUE 16
2 0 LOAD_FAST 0 (foo) 3 LOAD_FAST 1 (bar) 6 COMPARE_OP 3 (!=) 9 POP_JUMP_IF_FALSE 16
In this case, unless there was a difference in the amount of work required for each comparison, it's unlikely you'd see any performance difference at all.
However, note that the two versions won't always be logically identical , as it will depend on the implementations of
__ne__ for the objects in question. Per the data model documentation:
There are no implied relationships among the comparison operators. The truth of
x==ydoes not imply that
>>> class Dummy(object): def __eq__(self, other): return True def __ne__(self, other): return True >>> not Dummy() == Dummy() False >>> Dummy() != Dummy() True
Finally, and perhaps most importantly: in general, where the two are logically identical,
x != y is much more readable than
not x == y.
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