Python mock multiple return values
I am using pythons mock.patch and would like to change the return value for each call. Here is the caveat: the function being patched has no inputs, so I can not change the return value based on the input.
Here is my code for reference.
def get_boolean_response(): response = io.prompt('y/n').lower() while response not in ('y', 'n', 'yes', 'no'): io.echo('Not a valid input. Try again']) response = io.prompt('y/n').lower() return response in ('y', 'yes')
My Test code:
@mock.patch('io') def test_get_boolean_response(self, mock_io): #setup mock_io.prompt.return_value = ['x','y'] result = operations.get_boolean_response() #test self.assertTrue(result) self.assertEqual(mock_io.prompt.call_count, 2)
io.prompt is just a platform independent (python 2 and 3) version of "input". So ultimately I am trying to mock out the users input. I have tried using a list for the return value, but that doesn't seam to work.
You can see that if the return value is something invalid, I will just get an infinite loop here. So I need a way to eventually change the return value, so that my test actually finishes.
(another possible way to answer this question could be to explain how I could mimic user input in a unit-test)
Not a dup of this question mainly because I do not have the ability to vary the inputs.
One of the comments of the Answer on this question is along the same lines, but no answer/comment has been provided.
You can assign an iterable to
side_effect, and the mock will return the next value in the sequence each time it is called:
>>> from unittest.mock import Mock >>> m = Mock() >>> m.side_effect = ['foo', 'bar', 'baz'] >>> m() 'foo' >>> m() 'bar' >>> m() 'baz'
If _sideeffect is an iterable then each call to the mock will return the next value from the iterable.
As an aside, the test
response is not 'y' or 'n' or 'yes' or 'no' will not work; you are asking if the expression
(response is not 'y') is true, or
'y' is true (always the case, a non-empty string is always true), etc. The various expressions on either side of
or operators are independent. See How do I test one variable against multiple values?
You should also not use
is to test against a string. The CPython interpreter may reuse string objects under certain circumstances, but this is not behaviour you should count on.
As such, use:
response not in ('y', 'n', 'yes', 'no')
instead; this will use equality tests (
==) to determine if
response references a string with the same contents (value).
The same applies to
response == 'y' or 'yes'; use
response in ('y', 'yes') instead.