# Generate 'n' unique random numbers within a range

I know how to generate a random number within a range in Python.

```    random.randint(numLow, numHigh)
```

And I know I can put this in a loop to generate n amount of these numbers

```    for x in range (0, n):
listOfNumbers.append(random.randint(numLow, numHigh))
```

However, I need to make sure each number in that list is unique. Other than a load of conditional statements is there a straightforward way of generating n number of unique random numbers?

EDIT: The important thing is that each number in the list is different to the others..

So

[12, 5, 6, 1] = good

But

[12, 5, 5, 1] = bad, because the number 5 occurs twice.

If you just need sampling without replacement:

```    >>> import random
>>> random.sample(range(1, 100), 3)
[77, 52, 45]
```

random.sample takes a population and a sample size `k` and returns `k` random members of the population.

If you have to control for the case where `k` is larger than `len(population)`, you need to be prepared to catch a `ValueError`:

```    >>> try:
...   random.sample(range(1, 2), 3)
... except ValueError:
...   print('Sample size exceeded population size.')
...
Sample size exceeded population size
```

From: stackoverflow.com/q/22842289