# Access multiple elements of list knowing their index

I need to choose some elements from the given list, knowing their index. Let say I would like to create a new list, which contains element with index 1, 2, 5, from given list [-2, 1, 5, 3, 8, 5, 6]. What I did is:

```
a = [-2,1,5,3,8,5,6]
b = [1,2,5]
c = [ a[i] for i in b]
```

Is there any better way to do it? something like c = a[b] ?

You can use `operator.itemgetter`

:

```
from operator import itemgetter
a = [-2, 1, 5, 3, 8, 5, 6]
b = [1, 2, 5]
print itemgetter(*b)(a)
# Result:
(1, 5, 5)
```

Or you can use numpy:

```
import numpy as np
a = np.array([-2, 1, 5, 3, 8, 5, 6])
b = [1, 2, 5]
print list(a[b])
# Result:
[1, 5, 5]
```

But really, your current solution is fine. It's probably the neatest out of all of them.

From: stackoverflow.com/q/18272160

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