Why does random.shuffle return None?

Why is random.shuffle returning None in python?

    >>> x = ['foo','bar','black','sheep']
    >>> from random import shuffle
    >>> print shuffle(x)

How do I get the shuffled value instead of None?

random.shuffle() changes the x list in place.

Python API methods that alter a structure in-place generally return None, not the modified data structure.

If you wanted to create a new randomly-shuffled list based of an existing one, where the existing list is kept in order, you could use random.sample() with the full length of the input:

    x = ['foo', 'bar', 'black', 'sheep']
    random.sample(x, len(x))

You could also use sorted() with random.random() for a sorting key:

    shuffled = sorted(x, key=lambda k: random.random())

but this invokes sorting (an O(NlogN) operation), while sampling to the input length only takes O(N) operations (the same process as random.shuffle() is used, swapping out random values from a shrinking pool).


    >>> import random
    >>> x = ['foo', 'bar', 'black', 'sheep']
    >>> random.sample(x, len(x))
    ['bar', 'sheep', 'black', 'foo']
    >>> sorted(x, key=lambda k: random.random())
    ['sheep', 'foo', 'black', 'bar']
    >>> x
    ['foo', 'bar', 'black', 'sheep']

From: stackoverflow.com/q/17649875

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