TypeError: Missing 1 required positional argument: 'self'
I am new to python and have hit a wall. I followed several tutorials but cant get past the error:
Traceback (most recent call last): File "C:\Users\Dom\Desktop\test\test.py", line 7, in <module> p = Pump.getPumps() TypeError: getPumps() missing 1 required positional argument: 'self'
I examined several tutorials but there doesn't seem to be anything different from my code. The only thing I can think of is that python 3.3 requires different syntax.
# test script from lib.pump import Pump print ("THIS IS A TEST OF PYTHON") # this prints p = Pump.getPumps() print (p)
import pymysql class Pump: def __init__(self): print ("init") # never prints def getPumps(self): # Open database connection # some stuff here that never gets executed because of error
If I understand correctly "self" is passed to the constructor and methods automatically. What am I doing wrong here?
I am using windows 8 with python 3.3.2
You need to instantiate a class instance here.
p = Pump() p.getPumps()
Small example -
>>> class TestClass: def __init__(self): print "in init" def testFunc(self): print "in Test Func" >>> testInstance = TestClass() in init >>> testInstance.testFunc() in Test Func
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