How can I obtain the element-wise logical NOT of a pandas Series?

I have a pandas Series object containing boolean values. How can I get a series containing the logical NOT of each value?

For example, consider a series containing:

    True
    True
    True
    False

The series I'd like to get would contain:

    False
    False
    False
    True

This seems like it should be reasonably simple, but apparently I've misplaced my mojo =(

To invert a boolean Series, use ~s:

    In [7]: s = pd.Series([True, True, False, True])

    In [8]: ~s
    Out[8]: 
    0    False
    1    False
    2     True
    3    False
    dtype: bool

Using Python2.7, NumPy 1.8.0, Pandas 0.13.1:

    In [119]: s = pd.Series([True, True, False, True]*10000)

    In [10]:  %timeit np.invert(s)
    10000 loops, best of 3: 91.8 µs per loop

    In [11]: %timeit ~s
    10000 loops, best of 3: 73.5 µs per loop

    In [12]: %timeit (-s)
    10000 loops, best of 3: 73.5 µs per loop

As of Pandas 0.13.0, Series are no longer subclasses of numpy.ndarray; they are now subclasses of pd.NDFrame. This might have something to do with why np.invert(s) is no longer as fast as ~s or -s.

Caveat: timeit results may vary depending on many factors including hardware, compiler, OS, Python, NumPy and Pandas versions.

From: stackoverflow.com/q/15998188